Could someone please help me with this probability and statistics problem? Prove both algebraically

/in /by

Could someone please help me with this probability and statistics problem?

Prove both algebraically and combinatorially (in terms of selections) that

if n1 + n2 + n3 then (n choose n1) = (n choose n1) (n-n1 choose n2)

It’s hard to write out the form of (n choose n1) in plain text basically

(n choose n1) equals to

( n )

(n1, n2, n3). Same for

(n-n1)

( n2 )

Thank you so much in advance to anyone who can help on this problem.

 
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